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Channel: Introductory Quantum, trouble with this boundary condition and potential - Physics Stack Exchange
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Answer by Tim Crosby for Introductory Quantum, trouble with this boundary...

No they are not the same, to make them equal we have to make the constants proportionate$ Ae^{ikx} - Ae^{-ikx}$$A(\cos(kx) + i\sin(kx)) + A(\cos(-kx) + i\sin(-kx))$$A(2i\sin(kx))$Now this only proves...

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Answer by jinawee for Introductory Quantum, trouble with this boundary...

The choice of the constants $A$ and $B$ depends on the form of the solution. You could have denote one pair of constanst by $A$ and $B$, and the other by $C$ and $D$.A possible solution is $\psi...

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Introductory Quantum, trouble with this boundary condition and potential

Working on problem 2.40 from Griffiths but can't seem to understand the first boundary condition.We are given the potential $V(x) = \left\{\begin{matrix}\infty & x < 0\\...

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